JEE Main 20238 Apr, Evening shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002Let A={θ∈(0,2π):1+2isinθ1−isinθA=\left\{\theta \in(0,2 \pi): \frac{1+2 i \sin \theta}{1-i \sin \theta}\right.A={θ∈(0,2π):1−isinθ1+2isinθ is purely imaginary }\}}. Then the sum of the elements in A\mathrm{A}A is :AOption A. 3π3 \pi3πBOption B. π\piπCOption C. 2π2 \pi2πDOption D. 4π4 \pi4πCheckSkip · show solution
