JEE Main 202230 Jun, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002Let A=[1−2αα2−1]A = \left[ {\matrix{ 1 & { - 2} & \alpha \cr \alpha & 2 & { - 1} \cr } } \right]A=[1α−22α−1] and B=[2α−124−5], α∈CB = \left[ {\matrix{ 2 & \alpha \cr { - 1} & 2 \cr 4 & { - 5} \cr } } \right],\,\alpha \in CB=2−14α2−5,α∈C. Then the absolute value of the sum of all values of α\alphaα for which det(AB) = 0 is :AOption A. 3BOption B. 4COption C. 2DOption D. 5CheckSkip · show solution
