JEE Main 2004Annual, Paper 1MathematicsMediumMatrices and Determinants245× since 2002Let A=(1−1121−3111).A = \left( {\matrix{ 1 & { - 1} & 1 \cr 2 & 1 & { - 3} \cr 1 & 1 & 1 \cr } } \right).A=121−1111−31. and 101010 B=(422−50α1−23)B = \left( {\matrix{ 4 & 2 & 2 \cr { - 5} & 0 & \alpha \cr 1 & { - 2} & 3 \cr } } \right)B=4−5120−22α3. if BBB is the inverse of matrix AAA, then α\alphaα isAOption A. 555BOption B. −1-1−1COption C. 222DOption D. −2-2−2CheckSkip · show solution
