JEE Main 202225 Jul, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002Let A=(2−1−110−11−10)A=\left(\begin{array}{rrr}2 & -1 & -1 \\ 1 & 0 & -1 \\ 1 & -1 & 0\end{array}\right)A=211−10−1−1−10 and B=A−IB=A-IB=A−I. If ω=3i−12\omega=\frac{\sqrt{3} i-1}{2}ω=23i−1, then the number of elements in the set{n∈{1,2,…,100}:An+(ωB)n=A+B}\operatorname{set}\left\{n \in\{1,2, \ldots, 100\}: A^{n}+(\omega B)^{n}=A+B\right\}set{n∈{1,2,…,100}:An+(ωB)n=A+B} is equal to ____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
