JEE Main 202330 Jan, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002Let A=(mnpq),d=∣A∣≠0A=\left(\begin{array}{cc}\mathrm{m} & \mathrm{n} \\ \mathrm{p} & \mathrm{q}\end{array}\right), \mathrm{d}=|\mathrm{A}| \neq 0A=(mpnq),d=∣A∣=0 and ∣A−d(AdjA)∣=0\mathrm{|A-d(A d j A)|=0}∣A−d(AdjA)∣=0. ThenAOption A. 1+d2=m2+q21+\mathrm{d}^{2}=\mathrm{m}^{2}+\mathrm{q}^{2}1+d2=m2+q2BOption B. 1+d2=(m+q)21+d^{2}=(m+q)^{2}1+d2=(m+q)2COption C. (1+d)2=m2+q2(1+d)^{2}=m^{2}+q^{2}(1+d)2=m2+q2DOption D. (1+d)2=(m+q)2(1+d)^{2}=(m+q)^{2}(1+d)2=(m+q)2CheckSkip · show solution
