JEE Main 202227 Jul, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002Let A=(12−2−5)A=\left(\begin{array}{cc}1 & 2 \\ -2 & -5\end{array}\right)A=(1−22−5). Let α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R be such that αA2+βA=2I\alpha A^{2}+\beta A=2 IαA2+βA=2I. Then α+β\alpha+\betaα+β is equal toAOption A. −-−10BOption B. −-−6COption C. 6DOption D. 10CheckSkip · show solution
