JEE Main 202310 Apr, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002Let a common tangent to the curves y2=4x{y^2} = 4xy2=4x and (x−4)2+y2=16{(x - 4)^2} + {y^2} = 16(x−4)2+y2=16 touch the curves at the points P and Q. Then (PQ)2{(PQ)^2}(PQ)2 is equal to __________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
