Let 'a' be a real number such that the function f(x) = ax² + 6x - 15, x R is increasing in (- ∞,3/4) and decreasing in (3/4,∞). Then the function g(x) = ax² - 6x + 15, x R has a:

Limit, Continuity and Differentiability: JEE Main 2021 Mathematics question

JEE Main 2021 · 20 Jul, Morning shift · Q2656

JEE Main 202120 Jul, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

Let 'a' be a real number such that the function f(x) = ax² + 6x

-

15, x

\in

R is increasing in

\left( { - \infty ,{3 \over 4}} \right)

and decreasing in

\left( {{3 \over 4},\infty } \right)

. Then the function g(x) = ax²

-

6x + 15, x

\in

R has a :