JEE Main 202116 Mar, Evening shiftMathematicsMediumSequence and Series179× since 2002Let 116{1 \over {16}}161, a and b be in G.P. and 1a{1 \over a}a1, 1b{1 \over b}b1, 6 be in A.P., where a, b > 0. Then 72(a + b) is equal to ___________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution