JEE Main 20211 Sep, Evening shiftMathematicsMediumSequence and Series179× since 2002Let a₁, a₂, ..........., a₂₁ be an AP such that ∑n=1201anan+1=49\sum\limits_{n = 1}^{20} {{1 \over {{a_n}{a_{n + 1}}}} = {4 \over 9}}n=1∑20anan+11=94. If the sum of this AP is 189, then a₆a₁₆ is equal to :AOption A. 57BOption B. 72COption C. 48DOption D. 36CheckSkip · show solution