JEE Main 202227 Jun, Morning shiftMathematicsMediumIntegral Calculus369× since 2002Let A1={(x,y):∣x∣≤y2,∣x∣+2y≤8}{A_1} = \left\{ {(x,y):|x| \le {y^2},|x| + 2y \le 8} \right\}A1={(x,y):∣x∣≤y2,∣x∣+2y≤8} and A2={(x,y):∣x∣+∣y∣≤k}{A_2} = \left\{ {(x,y):|x| + |y| \le k} \right\}A2={(x,y):∣x∣+∣y∣≤k}. If 27 (Area A₁) = 5 (Area A₂), then k is equal to :Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
