JEE Main 202621 Jan, Evening shiftMathematicsEasySequence and Series179× since 2002Let a1,a22,a322,…,a1029a_1, \frac{a_2}{2}, \frac{a_3}{2^2}, \ldots, \frac{a_{10}}{2^9}a1,2a2,22a3,…,29a10 be a G.P. of common ratio 12\frac{1}{\sqrt2}21. If a1+a2+…+a10=62a_1+a_2+\ldots+a_{10}=62a1+a2+…+a10=62, then a1a_1a1 is equal to :AOption A. 2−1\sqrt2-12−1BOption B. 2−22-\sqrt22−2COption C. 2(2−2)2(2-\sqrt2)2(2−2)DOption D. 2(2−1)2(\sqrt2-1)2(2−1)CheckSkip · show solution
