Let f(x) = (1 - tan x)/(4x - π), x ≠ (π)/4, x [ 0,(π)/2 ]. If f(x) is continuous in [ 0,(π)/2 ], then f((π)/4) is

Limit, Continuity and Differentiability: JEE Main 2004 Mathematics question

JEE Main 2004 · Annual, Paper 1 · Q4125

JEE Main 2004Annual, Paper 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002

Let

f(x) = {{1 - \tan x} \over {4x - \pi }}

x \ne {\pi \over 4}

x \in \left[ {0,{\pi \over 2}} \right]

. If

f(x)

is continuous in

\left[ {0,{\pi \over 2}} \right]

, then

f\left( {{\pi \over 4}} \right)

JEE Main 2004 · Annual, Paper 1 · Q4125

JEE Main 2004Annual, Paper 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002

Let

f(x) = {{1 - \tan x} \over {4x - \pi }}

x \ne {\pi \over 4}

x \in \left[ {0,{\pi \over 2}} \right]

. If

f(x)

is continuous in

\left[ {0,{\pi \over 2}} \right]

, then

f\left( {{\pi \over 4}} \right)