JEE Main 202225 Jun, Morning shiftPhysicsEasyKinematics177× since 2002A→\overrightarrow AA is a vector quantity such that ∣A→∣|\overrightarrow A |∣A∣ = non-zero constant. Which of the following expression is true for A→\overrightarrow AA ?AOption A. A→ . A→=0\overrightarrow A \,.\,\overrightarrow A = 0A.A=0BOption B. A→×A→<0\overrightarrow A \times \overrightarrow A < 0A×A<0COption C. A→×A→=0\overrightarrow A \times \overrightarrow A = 0A×A=0DOption D. A→×A→>0\overrightarrow A \times \overrightarrow A > 0A×A>0CheckSkip · show solution
