JEE Main 202325 Jan, Evening shiftMathematicsEasyPermutations and Combinations98× since 2002∑k=0651−kC3\sum\limits_{k = 0}^6 {{}^{51 - k}{C_3}}k=0∑651−kC3 is equal to :AOption A. 51C4−45C4\mathrm{{}^{51}{C_4} - {}^{45}{C_4}}51C4−45C4BOption B. 51C3−45C3\mathrm{{}^{51}{C_3} - {}^{45}{C_3}}51C3−45C3COption C. 52C3−45C3\mathrm{{}^{52}{C_3} - {}^{45}{C_3}}52C3−45C3DOption D. 52C4−45C4\mathrm{{}^{52}{C_4} - {}^{45}{C_4}}52C4−45C4CheckSkip · show solution
