∫₆¹⁶ log e x² log e x² + log e (x² - 44x + 484) dx is equal to:

Integral Calculus: JEE Main 2021 Mathematics question

JEE Main 2021 · 27 Aug, Morning shift · Q3419

JEE Main 202127 Aug, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

\int\limits_6^{16} {{{{{\log }_e}{x^2}} \over {{{\log }_e}{x^2} + {{\log }_e}({x^2} - 44x + 484)}}dx}

is equal to :

JEE Main 2021 · 27 Aug, Morning shift · Q3419

JEE Main 202127 Aug, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

\int\limits_6^{16} {{{{{\log }_e}{x^2}} \over {{{\log }_e}{x^2} + {{\log }_e}({x^2} - 44x + 484)}}dx}

is equal to :