JEE Main 202324 Jan, Evening shiftMathematicsMediumIntegral Calculus369× since 2002∫324334489−4x2dx\int\limits_{{{3\sqrt 2 } \over 4}}^{{{3\sqrt 3 } \over 4}} {{{48} \over {\sqrt {9 - 4{x^2}} }}dx}432∫4339−4x248dx is equal to :AOption A. π2{\pi \over 2}2πBOption B. π3{\pi \over 3}3πCOption C. π6{\pi \over 6}6πDOption D. 2π2\pi2πCheckSkip · show solution
