JEE Main 202227 Jul, Evening shiftMathematicsMediumIntegral Calculus369× since 2002∫02(∣2x2−3x∣+[x−12])dx\int\limits_{0}^{2}\left(\left|2 x^{2}-3 x\right|+\left[x-\frac{1}{2}\right]\right) \mathrm{d} x0∫2(2x2−3x+[x−21])dx, where [t] is the greatest integer function, is equal to :AOption A. 76\frac{7}{6}67BOption B. 1912\frac{19}{12}1219COption C. 3112\frac{31}{12}1231DOption D. 32\frac{3}{2}23CheckSkip · show solution
