In the Young's double slit experiment, the distance between the slits varies in time as d(t) = d₀ + a₀ sin ω t; where d₀, ω and a₀ are constants. The difference between the largest fringe width and the smallest fringe width obtained over time is given as:

(B) 2λ D a₀ (d₀² - a₀²)

(A) (2λ D(d₀))/((d₀² - a₀²))

Optics: JEE Main 2021 Physics question

JEE Main 2021 · 25 Jul, Morning shift · Q8437

JEE Main 202125 Jul, Morning shiftPhysicsMediumOptics190× since 2002

In the Young's double slit experiment, the distance between the slits varies in time as d(t) = d₀ + a₀ sin

\omega

t; where d₀,

\omega

and a₀ are constants. The difference between the largest fringe width and the smallest fringe width obtained over time is given as :

JEE Main 2021 · 25 Jul, Morning shift · Q8437

JEE Main 202125 Jul, Morning shiftPhysicsMediumOptics190× since 2002

In the Young's double slit experiment, the distance between the slits varies in time as d(t) = d₀ + a₀ sin

\omega

t; where d₀,

\omega

and a₀ are constants. The difference between the largest fringe width and the smallest fringe width obtained over time is given as :