JEE Main 202228 Jul, Morning shiftPhysicsEasyOscillations and Waves185× since 2002In the wave equation y=0.5sin2πλ(400t−x) my=0.5 \sin \frac{2 \pi}{\lambda}(400 \mathrm{t}-x) \,\mathrm{m}y=0.5sinλ2π(400t−x)m the velocity of the wave will be:AOption A. 200 m/sBOption B. 2002\sqrt22 m/sCOption C. 400 m/sDOption D. 4002\sqrt22 m/sCheckSkip · show solution
