In the expansion of (9x-1/(3 x))¹⁸, x>0, if the term independent of x is (221)k, then k is equal to:

Binomial Theorem and Its Simple Applications: JEE Main 2026 Mathematics question

JEE Main 2026 · 4 Apr, Evening shift · Q9

JEE Main 20264 Apr, Evening shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002

In the expansion of

\left(9x-\frac{1}{3\sqrt x}\right)^{18}

x>0

, if the term independent of

x

(221)k

, then

k

is equal to: