In the expansion of (1+x)(1-x²)(1+3/x+3/(x²)+1/(x³))⁵, x ≠ 0, the sum of the coefficients of x³ and x⁻¹³ is equal to _ _ _ _ _.

Binomial Theorem and Its Simple Applications: JEE Main 2024 Mathematics question

JEE Main 2024 · 31 Jan, Morning shift · Q32

JEE Main 202431 Jan, Morning shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002

In the expansion of

(1+x)\left(1-x^2\right)\left(1+\frac{3}{x}+\frac{3}{x^2}+\frac{1}{x^3}\right)^5, x \neq 0

, the sum of the coefficients of

x^3

and

x^{-13}

is equal to __________.

Your answerType your answer. Integers and decimals are accepted.