In a series LR circuit with X L =R, power factor P₁. If a capacitor of capacitance C with X C =X L is added to the circuit the power factor becomes P₂. The ratio of P₁ to P₂ will be:

Electromagnetic Induction and Alternating Currents: JEE Main 2023 Physics question

JEE Main 2023 · 30 Jan, Morning shift · Q5916

JEE Main 202330 Jan, Morning shiftPhysicsEasyElectromagnetic Induction and Alternating Currents149× since 2002

In a series LR circuit with

\mathrm{X_L=R}

, power factor P₁. If a capacitor of capacitance C with

\mathrm{X_C=X_L}

is added to the circuit the power factor becomes P₂. The ratio of P₁ to P₂ will be :

JEE Main 2023 · 30 Jan, Morning shift · Q5916

JEE Main 202330 Jan, Morning shiftPhysicsEasyElectromagnetic Induction and Alternating Currents149× since 2002

In a series LR circuit with

\mathrm{X_L=R}

, power factor P₁. If a capacitor of capacitance C with

\mathrm{X_C=X_L}

is added to the circuit the power factor becomes P₂. The ratio of P₁ to P₂ will be :