Electromagnetic Induction and Alternating Currents: JEE Main 2022 Physics question

In a series $L R$ circuit $X_{L}=R$ and power factor of the circuit is $P_{1}$. When capacitor with capacitance $C$ such that $X_{L}=X_{C}$ is put in series, the power factor becomes $P_{2}$. The ratio $\frac{P_{1}}{P_{2}}$ is: