JEE Main 20248 Apr, Evening shiftPhysicsMediumAtoms and Nuclei183× since 2002In a hypothetical fission reaction 92X236→56Y141+36Z92+3R{ }_{92} X^{236} \rightarrow{ }_{56} \mathrm{Y}^{141}+{ }_{36} Z^{92}+3 R92X236→56Y141+36Z92+3R The identity of emitted particles (R) is :AOption A. ProtonBOption B. NeutronCOption C. ElectronDOption D. γ\gammaγ-radiationsCheckSkip · show solution