If z = (3)/2 + i/2(i = √(- 1)), then (1 + iz + z⁵ + iz⁸)⁹ is equal to:

Complex Numbers and Quadratic Equations: JEE Main 2019 Mathematics question

JEE Main 2019 · 8 Apr, Evening shift · Q3240

JEE Main 20198 Apr, Evening shiftMathematicsHardComplex Numbers and Quadratic Equations264× since 2002

z = {{\sqrt 3 } \over 2} + {i \over 2}\left( {i = \sqrt { - 1} } \right)

, then (1 + iz + z⁵ + iz⁸)⁹ is equal to :

JEE Main 2019 · 8 Apr, Evening shift · Q3240

JEE Main 20198 Apr, Evening shiftMathematicsHardComplex Numbers and Quadratic Equations264× since 2002

z = {{\sqrt 3 } \over 2} + {i \over 2}\left( {i = \sqrt { - 1} } \right)

, then (1 + iz + z⁵ + iz⁸)⁹ is equal to :