JEE Main 202229 Jun, Evening shiftMathematicsHardDifferential Equations163× since 2002If y = y(x) is the solution of the differential equation (1+e2x)dydx+2(1+y2)ex=0\left( {1 + {e^{2x}}} \right){{dy} \over {dx}} + 2\left( {1 + {y^2}} \right){e^x} = 0(1+e2x)dxdy+2(1+y2)ex=0 and y (0) = 0, then 6(y′(0)+(y(loge3))2)6\left( {y'(0) + {{\left( {y\left( {{{\log }_e}\sqrt 3 } \right)} \right)}^2}} \right)6(y′(0)+(y(loge3))2) is equal toAOption A. 2BOption B. −-−2COption C. −-−4DOption D. −-−1CheckSkip · show solution
