If y = y(x) is the solution of the differential equation, dy/dx + 2y tan x = sin x,y((π)/3) = 0, then the maximum value of the function y(x) over R is equal to:

Differential Equations: JEE Main 2021 Mathematics question

JEE Main 2021 · 16 Mar, Morning shift · Q3527

JEE Main 202116 Mar, Morning shiftMathematicsMediumDifferential Equations163× since 2002

If y = y(x) is the solution of the differential equation,

{{dy} \over {dx}} + 2y\tan x = \sin x,y\left( {{\pi \over 3}} \right) = 0

, then the maximum value of the function y(x) over R is equal to:

JEE Main 2021 · 16 Mar, Morning shift · Q3527

JEE Main 202116 Mar, Morning shiftMathematicsMediumDifferential Equations163× since 2002

If y = y(x) is the solution of the differential equation,

{{dy} \over {dx}} + 2y\tan x = \sin x,y\left( {{\pi \over 3}} \right) = 0

, then the maximum value of the function y(x) over R is equal to: