JEE Main 2013Session, Shift 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002If y=sec(tan−1x),y = \sec \left( {{{\tan }^{ - 1}}x} \right),y=sec(tan−1x), then dydx{{{dy} \over {dx}}}dxdy at x=1x=1x=1 is equal to :AOption A. 12{1 \over {\sqrt 2 }}21BOption B. 12{1 \over 2}21COption C. 111DOption D. 2\sqrt 22CheckSkip · show solution