JEE Main 20241 Feb, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002If y=(x+1)(x2−x)xx+x+x+115(3cos2x−5)cos3xy=\frac{(\sqrt{x}+1)\left(x^2-\sqrt{x}\right)}{x \sqrt{x}+x+\sqrt{x}}+\frac{1}{15}\left(3 \cos ^2 x-5\right) \cos ^3 xy=xx+x+x(x+1)(x2−x)+151(3cos2x−5)cos3x, then 96y′(π6)96 y^{\prime}\left(\frac{\pi}{6}\right)96y′(6π) is equal to :Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
