JEE Main 2006Annual, Paper 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002If xm.yn=(x+y)m+n,{x^m}.{y^n} = {\left( {x + y} \right)^{m + n}},xm.yn=(x+y)m+n, then dydx{{{dy} \over {dx}}}dxdy isAOption A. yx{y \over x}xyBOption B. x+yxy{{x + y} \over {xy}}xyx+yCOption C. xyxyxyDOption D. xy{x \over y}yxCheckSkip · show solution