JEE Main 202131 Aug, Evening shiftMathematicsMediumIntegral Calculus369× since 2002If [x] is the greatest integer ≤\le≤ x, then π2∫02(sinπx2)(x−[x])[x]dx{\pi ^2}\int\limits_0^2 {\left( {\sin {{\pi x} \over 2}} \right)(x - [x]} {)^{[x]}}dxπ20∫2(sin2πx)(x−[x])[x]dx is equal to :AOption A. 2(π\piπ −-− 1)BOption B. 4(π\piπ −-− 1)COption C. 4(π\piπ + 1)DOption D. 2(π\piπ + 1)CheckSkip · show solution
