JEE Main 2004Annual, Paper 1MathematicsEasyLimit, Continuity and Differentiability420× since 2002If x=ey+ey+ey+.....∞x = {e^{y + {e^y} + {e^{y + .....\infty }}}}x=ey+ey+ey+.....∞ , x>0,x > 0,x>0, then dydx{{{dy} \over {dx}}}dxdy isAOption A. 1+xx{{1 + x} \over x}x1+xBOption B. 1x{1 \over x}x1COption C. 1−xx{{1 - x} \over x}x1−xDOption D. x1+x{x \over {1 + x}}1+xxCheckSkip · show solution
