JEE Main 20203 Sep, Evening shiftMathematicsMediumDifferential Equations163× since 2002If x³dy + xy dx = x²dy + 2y dx; y(2) = e and x > 1, then y(4) is equal to :AOption A. e2{{\sqrt e } \over 2}2eBOption B. 12+e{1 \over 2} + \sqrt e21+eCOption C. 32+e{3 \over 2} + \sqrt e23+eDOption D. 32e{3 \over 2}\sqrt e23eCheckSkip · show solution