JEE Main 2005Annual, Paper 1MathematicsMediumDifferential Equations163× since 2002If xdydx=y(logy−logx+1),x{{dy} \over {dx}} = y\left( {\log y - \log x + 1} \right),xdxdy=y(logy−logx+1), then the solution of the equation is :AOption A. ylog(xy)=cxy\log \left( {{x \over y}} \right) = cxylog(yx)=cxBOption B. xlog(yx)=cyx\log \left( {{y \over x}} \right) = cyxlog(xy)=cyCOption C. log(yx)=cx\log \left( {{y \over x}} \right) = cxlog(xy)=cxDOption D. log(xy)=cy\log \left( {{x \over y}} \right) = cylog(yx)=cyCheckSkip · show solution
