Sequence and Series: JEE Main 2022 Mathematics question

JEE Main 2022 · 24 Jun, Morning shift · Q5225

JEE Main 202224 Jun, Morning shiftMathematicsMediumSequence and Series179× since 2002

\{ {a_i}\} _{i = 1}^n

, where n is an even integer, is an arithmetic progression with common difference 1, and

\sum\limits_{i = 1}^n {{a_i} = 192} ,\,\sum\limits_{i = 1}^{n/2} {{a_{2i}} = 120}

, then n is equal to :

JEE Main 2022 · 24 Jun, Morning shift · Q5225

JEE Main 202224 Jun, Morning shiftMathematicsMediumSequence and Series179× since 2002

\{ {a_i}\} _{i = 1}^n

, where n is an even integer, is an arithmetic progression with common difference 1, and

\sum\limits_{i = 1}^n {{a_i} = 192} ,\,\sum\limits_{i = 1}^{n/2} {{a_{2i}} = 120}

, then n is equal to :

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