JEE Main 202431 Jan, Evening shiftPhysicsEasyKinematics177× since 2002If two vectors A⃗\vec{A}A and B⃗\vec{B}B having equal magnitude RRR are inclined at angle θ\thetaθ, thenAOption A. ∣A⃗+B⃗∣=2Rcos(θ2)|\vec{A}+\vec{B}|=2 R \cos \left(\frac{\theta}{2}\right)∣A+B∣=2Rcos(2θ)BOption B. ∣A⃗−B⃗∣=2Rcos(θ2)|\vec{A}-\vec{B}|=2 R \cos \left(\frac{\theta}{2}\right)∣A−B∣=2Rcos(2θ)COption C. ∣A⃗−B⃗∣=2Rsin(θ2)|\vec{A}-\vec{B}|=\sqrt{2} R \sin \left(\frac{\theta}{2}\right)∣A−B∣=2Rsin(2θ)DOption D. ∣A⃗+B⃗∣=2Rsin(θ2)|\vec{A}+\vec{B}|=2 R \sin \left(\frac{\theta}{2}\right)∣A+B∣=2Rsin(2θ)CheckSkip · show solution
