JEE Main 202310 Apr, Evening shiftMathematicsMediumSequence and Series179× since 2002If Sn=4+11+21+34+50+…\mathrm{S}_{n}=4+11+21+34+50+\ldotsSn=4+11+21+34+50+… to nnn terms, then 160( S29−S9)\frac{1}{60}\left(\mathrm{~S}_{29}-\mathrm{S}_{9}\right)601( S29−S9) is equal to :AOption A. 227BOption B. 226COption C. 220DOption D. 223CheckSkip · show solution