JEE Main 202621 Jan, Morning shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002If x2+x+1=0x^2+x+1=0x2+x+1=0, then the value of (x+1x)4+(x2+1x2)4+(x3+1x3)4+…+(x25+1x25)4\left(x+\frac{1}{x}\right)^4+\left(x^2+\frac{1}{x^2}\right)^4+\left(x^3+\frac{1}{x^3}\right)^4+\ldots+\left(x^{25}+\frac{1}{x^{25}}\right)^4(x+x1)4+(x2+x21)4+(x3+x31)4+…+(x25+x251)4 is :AOption A. 162BOption B. 145COption C. 175DOption D. 128CheckSkip · show solution
