JEE Main 2004Annual, Paper 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002If 2a+3b+6c=02a+3b+6c=02a+3b+6c=0, then at least one root of the equation ax2+bx+c=0a{x^2} + bx + c = 0ax2+bx+c=0 lies in the intervalAOption A. (1,3)(1, 3)(1,3)BOption B. (1,2)(1, 2)(1,2)COption C. (2,3)(2, 3)(2,3)DOption D. (0,1)(0, 1)(0,1)CheckSkip · show solution
