JEE Main 20231 Feb, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002If y(x)=xx,x>0y(x)=x^{x},x > 0y(x)=xx,x>0, then y′′(2)−2y′(2)y''(2)-2y'(2)y′′(2)−2y′(2) is equal toAOption A. 4(loge2)2+24(\log_{e}2)^{2}+24(loge2)2+2BOption B. 8loge2−28\log_{e}2-28loge2−2COption C. 4loge2+24\log_{e}2+24loge2+2DOption D. 4(loge2)2−24(\log_{e}2)^{2}-24(loge2)2−2CheckSkip · show solution
