JEE Main 20249 Apr, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002If logey=3sin−1x\log _e y=3 \sin ^{-1} xlogey=3sin−1x, then (1−x2)y′′−xy′(1-x^2) y^{\prime \prime}-x y^{\prime}(1−x2)y′′−xy′ at x=12x=\frac{1}{2}x=21 is equal toAOption A. 9eπ/29 e^{\pi / 2}9eπ/2BOption B. 9eπ/69 e^{\pi / 6}9eπ/6COption C. 3eπ/23 e^{\pi / 2}3eπ/2DOption D. 3eπ/63 e^{\pi / 6}3eπ/6CheckSkip · show solution
