JEE Main 20209 Jan, Morning shiftMathematicsHardVector Algebra184× since 2002If the vectors, p→=(a+1)i^+aj^+ak^\overrightarrow p = \left( {a + 1} \right)\widehat i + a\widehat j + a\widehat kp=(a+1)i+aj+ak, q→=ai^+(a+1)j^+ak^\overrightarrow q = a\widehat i + \left( {a + 1} \right)\widehat j + a\widehat kq=ai+(a+1)j+ak and r→=ai^+aj^+(a+1)k^(a∈R)\overrightarrow r = a\widehat i + a\widehat j + \left( {a + 1} \right)\widehat k\left( {a \in R} \right)r=ai+aj+(a+1)k(a∈R) are coplanar and 3(p→.q→)2−λ∣r→×q→∣2=03{\left( {\overrightarrow p .\overrightarrow q } \right)^2} - \lambda \left| {\overrightarrow r \times \overrightarrow q } \right|^2 = 03(p.q)2−λr×q2=0, then the value of λ\lambdaλ is ______.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution