JEE Main 20179 Apr, Morning shiftMathematicsHardVector Algebra184× since 2002If the vector b→=3j^+4k^\overrightarrow b = 3\widehat j + 4\widehat kb=3j+4k is written as the sum of a vector b1→,\overrightarrow {{b_1}} ,b1, paralel to a→=i^+j^\overrightarrow a = \widehat i + \widehat ja=i+j and a vector b2→,\overrightarrow {{b_2}} ,b2, perpendicular to a→,\overrightarrow a ,a, then b1→×b2→\overrightarrow {{b_1}} \times \overrightarrow {{b_2}}b1×b2 is equal to :AOption A. −3i^+3j^−9k^- 3\widehat i + 3\widehat j - 9\widehat k−3i+3j−9kBOption B. 6i^−6j^+92k^6\widehat i - 6\widehat j + {9 \over 2}\widehat k6i−6j+29kCOption C. −6i^+6j^−92k^- 6\widehat i + 6\widehat j - {9 \over 2}\widehat k−6i+6j−29kDOption D. 3i^−3j^+9k^3\widehat i - 3\widehat j + 9\widehat k3i−3j+9kCheckSkip · show solution
