JEE Main 202125 Jul, Morning shiftMathematicsMediumSequence and Series179× since 2002If the value of (1+23+632+1033+....upto ∞)log(0.25)(13+132+133+....upto ∞){\left( {1 + {2 \over 3} + {6 \over {{3^2}}} + {{10} \over {{3^3}}} + ....upto\,\infty } \right)^{{{\log }_{(0.25)}}\left( {{1 \over 3} + {1 \over {{3^2}}} + {1 \over {{3^3}}} + ....upto\,\infty } \right)}}(1+32+326+3310+....upto∞)log(0.25)(31+321+331+....upto∞) is lll, then lll² is equal to _______________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
