JEE Main 2003Annual, Paper 1MathematicsEasyCoordinate Geometry478× since 2002If the two circles (x−1)2 + (y−3)2= r2{(x - 1)^2}\, + \,{(y - 3)^2} = \,{r^2}(x−1)2+(y−3)2=r2 and x2 + y2− 8x + 2y + 8 =0\,{x^2}\, + \,{y^2} - \,8x\, + \,2y\, + \,\,8\,\, = 0x2+y2−8x+2y+8=0 intersect in two distinct point, then :AOption A. r>2r > 2r>2BOption B. 2<r<82 < r < 82<r<8COption C. r<2r < 2r<2DOption D. r=2.r = 2.r=2.CheckSkip · show solution
