JEE Main 202227 Jul, Evening shiftMathematicsMediumMathematical Reasoning115× since 2008If the truth value of the statement (P∧(∼R))→((∼R)∧Q)(P \wedge(\sim R)) \rightarrow((\sim R) \wedge Q)(P∧(∼R))→((∼R)∧Q) is F, then the truth value of which of the following is F\mathrm{F}F ?AOption A. P∨Q→ ∼R\mathrm{P} \vee \mathrm{Q} \rightarrow \,\sim \mathrm{R}P∨Q→∼RBOption B. R∨Q→ ∼P\mathrm{R} \vee \mathrm{Q} \rightarrow \,\sim \mathrm{P}R∨Q→∼PCOption C. ∼(P∨Q)→∼R\sim(\mathrm{P} \vee \mathrm{Q}) \rightarrow \sim \mathrm{R}∼(P∨Q)→∼RDOption D. ∼(R∨Q)→ ∼P\sim(\mathrm{R} \vee \mathrm{Q}) \rightarrow \,\sim \mathrm{P}∼(R∨Q)→∼PCheckSkip · show solution
