If the third term in the binomial expansion of (1 + x^(log ₂x))⁵ equals 2560, then a possible value of x is -

Binomial Theorem and Its Simple Applications: JEE Main 2019 Mathematics question

JEE Main 2019 · 10 Jan, Morning shift · Q2921

JEE Main 201910 Jan, Morning shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002

If the third term in the binomial expansion of

{\left( {1 + {x^{{{\log }_2}x}}} \right)^5}

equals 2560, then a possible value of x is -

JEE Main 2019 · 10 Jan, Morning shift · Q2921

JEE Main 201910 Jan, Morning shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002

If the third term in the binomial expansion of

{\left( {1 + {x^{{{\log }_2}x}}} \right)^5}

equals 2560, then a possible value of x is -