If the tangent to the curve y = x/(x² - 3), x ρ,(x ≠ ± 3), at a point (α, β) ≠ (0, 0) on it is parallel to the line 2x + 6y – 11 = 0, then:

Limit, Continuity and Differentiability: JEE Main 2019 Mathematics question

JEE Main 2019 · 10 Apr, Evening shift · Q2768

JEE Main 201910 Apr, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002

If the tangent to the curve

y = {x \over {{x^2} - 3}}

x \in \rho ,\left( {x \ne \pm \sqrt 3 } \right)

, at a point (

\alpha

\beta

)

\ne

(0, 0) on it is parallel to the line 2x + 6y – 11 = 0, then :

JEE Main 2019 · 10 Apr, Evening shift · Q2768

JEE Main 201910 Apr, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002

If the tangent to the curve

y = {x \over {{x^2} - 3}}

x \in \rho ,\left( {x \ne \pm \sqrt 3 } \right)

, at a point (

\alpha

\beta

)

\ne

(0, 0) on it is parallel to the line 2x + 6y – 11 = 0, then :