Matrices and Determinants: JEE Main 2018 Mathematics question

JEE Main 2018 · Session, Shift 1 · Q4559

JEE Main 2018Session, Shift 1MathematicsMediumMatrices and Determinants245× since 2002

If the system of linear equations x + ky + 3z = 0 3x + ky - 2z = 0 2x + 4y - 3z = 0 has a non-zero solution (x, y, z), then

{{xz} \over {{y^2}}}

is equal to

JEE Main 2018 · Session, Shift 1 · Q4559

JEE Main 2018Session, Shift 1MathematicsMediumMatrices and Determinants245× since 2002

If the system of linear equations x + ky + 3z = 0 3x + ky - 2z = 0 2x + 4y - 3z = 0 has a non-zero solution (x, y, z), then

{{xz} \over {{y^2}}}

is equal to

More on Matrices and Determinants